CH1 Handout Review_page_10

CH1 Handout Review | page 10 | https://thedailydialectics.com/pdfs/education/calculus/calculus-2-2413-HCC/CH1 Handout Review/CH1 Handout Review.pdf

x2-1 4x -4 f(x) is not defined at x = 1. 25) f(x) = ,atx=1 25) (x + 1)(x -1) _ 4(x - 1) Now the function is continuous at x = 1. So, f(x) has a removable discontinuity at x = 1. f(x) can be redefined as f(x) = A(x +1). {x|= x2+1, x>0 x+1, x=0 1. £(0) = 1, So f(0) is defined. 2. lim f(x)=1 , lim…